Step 1: Transmission and Collision Detection Transmission Start (Bit time 0) : Bit 0 is sent by all stations except Station 2 and Station 7. Since more than one station transmits a '1', a collision occurs. All stations except Station 2 and Station 7 move to the next bit. Bit time 1 : Bit 1 is sent by Station 1, Station 4, Station 5, and Station 8. Again, multiple '1's cause a collision. Only Station 1, Station 4, Station 5, and Station 8 proceed to Bit time 2. Bit time 2 : Bit 2 is sent only by Station 8. Since Station 8 is the only station transmitting a '1' without any collision, it has the highest priority in this bit time. Explanation : At this point, we've determined that Station 8 has successfully transmitted more bits than any other station without encountering a collision. No other station continues beyond this bit time without conflict. Step 2: Winner Determination and Data Transmission Continued Transmission by Station 8 : Station 8 continues to transmit bits for Bit times 3, 4, 5, and 6. It faces no collisions since it's the only station transmitting. Data Transmission : Since no other station places a '1' that conflicts with Station 8's transmission from Bit time 2 onwards, Station 8 wins the transmission slot. The data transmitted by Station 8 is the sequence of bits it was set to transmit: 101110 . Explanation : Station 8 sends the data 101110 as it is the first to place all its bits on the bus without any other station placing a conflicting '1' at the same time. Final The station 8 sends the data 101110. This is deduced by observing that Station 8 was able to place its entire bit sequence on the bus without any collisions from Bit time 2 onward.

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: 8 stations will transmit data over a single channel. The data that each station wants to transmit is given in the table below. With the binary countdown protocol, find the number of the station that will transmit data and the data it transmits.

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