' : 8 stations will transmit data over a single channel. The data…

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Manu · Accepted Answer

Step 1: Transmission and Collision Detection Transmission Start (Bit time 0) : Bit 0 is sent by all stations except Station 2 and Station 7. Since more than one station transmits a '1', a collision occurs. All stations except Station 2 and Station 7 move to the next bit. Bit time 1 : Bit 1 is sent by Station 1, Station 4, Station 5, and Station 8. Again, multiple '1's cause a collision. Only Station 1, Station 4, Station 5, and Station 8 proceed to Bit time 2. Bit time 2 : Bit 2 is sent only by Station 8. Since Station 8 is the only station transmitting a '1' without any collision, it has the highest priority in this bit time. Explanation : At this point, we've determined that Station 8 has successfully transmitted more bits than any other station without encountering a collision. No other station continues beyond this bit time without conflict. Step 2: Winner Determination and Data Transmission Continued Transmission by Station 8 : Station 8 continues to transmit bits for Bit times 3, 4, 5, and 6. It faces no collisions since it's the only station transmitting. Data Transmission : Since no other station places a '1' that conflicts with Station 8's transmission from Bit time 2 onwards, Station 8 wins the transmission slot. The data transmitted by Station 8 is the sequence of bits it was set to transmit: 101110 . Explanation : Station 8 sends the data 101110 as it is the first to place all its bits on the bus without any other station placing a conflicting '1' at the same time. Final  The station 8 sends the data 101110. This is deduced by observing that Station 8 was able to place its entire bit sequence on the bus without any collisions from Bit time 2 onward.

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